(Dis)content (Judgement of the Six)

(Dis)content (Judgement of the Six)

Matematika
[tex]\sf\huge \frac{4}{3} \times \frac{12}{4} + {2}^{ - 2} = [/tex]
.....................​


[tex]\sf\huge \frac{4}{3} \times \frac{12}{4} + {2}^{ - 2} = [/tex]
.....................​

= 4/3 × 12/4 + 2⁻²

= 4/3 × 12/4 + 1/(2²)

= (4 × 12/3 × 4) + 1/(2²)

= 48/12 + 1/(2²)

= 48/12 + 1/4

= (48 ÷ 3)/(12 ÷ 3) + 1/4

= 16/4 + 1/4

= (16 + 1)/4

= 17/4 Atau. 4 1/4

Jawaban:

[tex]\frac{4}{3} \times \frac{12}{4} + {2}^{ - 2} [/tex]

[tex] = \frac{1}{3} \times 12 + 2 {}^{ - 2} [/tex]

[tex] = 4 + 2 {}^{ - 2} [/tex]

[tex] = 4 + \frac{1}{2 {}^{2} } [/tex]

[tex] = 4 + \frac{1}{2 \times 2} [/tex]

[tex] = 4 + \frac{1}{4} [/tex]

[tex] = \frac{17}{4} [/tex]

[tex] = 4 \frac{1}{4} [/tex]

[tex]\boxed{ \colorbox{black}{ \sf{ \color{red}{༄Answer᭄By: ♡☞PunyaArkhan☜♡ ࿐ }}}}[/tex]

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